A particle of mass m is released from height h on a smooth curved surface which ends into a vertical loop of radius r, as shown. If h = 2r, then
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Verified by ExpertsThe correct answer is:
D
the particle breaks off at a height r < h < 2r
To reach the top of loop, particle must have a minimum speed of 
at the bottom of the loop, but v 2 = 2gh = 4gr , so the block won't reach the highest point of the track.
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